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Find The Area Cut Out Of The Cylinder X2+z2=100 By The Cylinder X2+y2=100. Question: Find The Area Cut Out Of The Cylinder X2+z2=100 By The Cylinder X2+y2=100. This problem has been solved! Find the area of the part of the cone x2 +y2 = 2z2 in the rst octant, cut out by the planes y= 0, and y= x= p 3, and the cylinder x2 + y2 = 4. ˚= 2z 2 x2 y )˚ x= 2x; ˚ y= 2y; ˚ z = 4z therefore, sec = p 4x 2+ 4y2 + 16z2 4jzj = q 4(x2 + y2) + 16z2 4z = p 24z 4z = q 3=2 But the triangle formed by y= 0 and y= x= p 3 as two of its sides has ...

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